Space-less custom language in syntax-editor

Dear Dess,

Yes i can elaborate.  i would like to write a code editor for a language which is not pre-defined in syntax editor.

This language is ZPL, and this is how it looks like:

https://www.zebra.com/content/dam/zebra/manuals/printers/common/programming/zpl-zbi2-pm-en.pdf

It is a barcoedlabel descriptor language, and to now i used an online editor, which shows the result as well on an image:

http://labelary.com/viewer.html

This is the best editor for now, but i would like to create a better one with your syntax editor. If i simply pick up the commands to WordTaggerBase  it results the above picture i attached in my first post. This language doenst have SPACEs between the command and  the command parameter.

For example a line of code looks like this:

^FO190,900^GB170,833,1^FS

This is how syntax editor colors it, if i add the keywords {"^FO","^GB","^FS"}

^FO190,900^GB170,833,1^FS

but this is how i would like to see it (i colored this manually:)

^FO190,900^GB170,833,1^FS

as yuo can see, since there is no space, the syntax editor thinks that ^FO190 is a command, not a command with parameter, so it doenst color it.

This is what i did so far, based on the articles you linked too:

Public Class ZPLTAGGER
    Inherits WordTaggerBase
    Private Shared ReadOnly Keywords As String() = New String() {"^", "XA", "XD", "FO", "FX", "GB", "XZ", "BY", "FD", "FS"}
    Private Shared ReadOnly Comments As String() = New String() {"#"}
    Private Shared ReadOnly Operators As String() = New String() {"+", "~", "*", "/"}
    Public Shared ReadOnly FruitsClassificationType As ClassificationType = New ClassificationType("Fruits")
    Private Shared ReadOnly Fruits As String() = New String() {"^FO", "^FD", "cherry"}
    Private Shared ReadOnly WordsToClassificationType As Dictionary(Of String, ClassificationType) = New Dictionary(Of String, ClassificationType)()
    Shared Sub New()
        WordsToClassificationType = New Dictionary(Of String, ClassificationType)()
        For Each keyword In Keywords
            WordsToClassificationType.Add(keyword, ClassificationTypes.Keyword)

        Next
        For Each preprocessor In Operators
            WordsToClassificationType.Add(preprocessor, ClassificationTypes.[Operator])
        Next
        For Each comment In Comments
            WordsToClassificationType.Add(comment, ClassificationTypes.Comment)
        Next
        For Each comment In Fruits
            WordsToClassificationType.Add(comment, FruitsClassificationType)
        Next
    End Sub
    Public Sub New(ByVal editor As RadSyntaxEditorElement)
        MyBase.New(editor)
    End Sub
    Protected Overrides Function GetWordsToClassificationTypes() As Dictionary(Of String, ClassificationType)
        Return ZPLTAGGER.WordsToClassificationType
    End Function
    Protected Overrides Function TryGetClassificationType(word As String, ByRef classificationType As ClassificationType) As Boolean
        Dim number As Integer
        If Integer.TryParse(word, number) Then
            classificationType = ClassificationTypes.NumberLiteral
            Return True
        End If
        Return MyBase.TryGetClassificationType(word, classificationType)
    End Function
End Class

And this is how i call it:

 Dim ZPLTAGGER As ZPLTAGGER = New ZPLTAGGER(Me.RADSYNTAX.SyntaxEditorElement)
        If Not Me.RADSYNTAX.TaggersRegistry.IsTaggerRegistered(ZPLTAGGER) Then
            Me.RADSYNTAX.TaggersRegistry.RegisterTagger(ZPLTAGGER)
        End If
        Me.RADSYNTAX.TextFormatDefinitions.AddLast(ClassificationTypes.NumberLiteral, New TextFormatDefinition(New SolidBrush(Color.Red)))
        Me.RADSYNTAX.TextFormatDefinitions.AddLast(ClassificationTypes.[Operator], New TextFormatDefinition(New SolidBrush(Color.YellowGreen)))
        Me.RADSYNTAX.TextFormatDefinitions.AddLast(ZPLTAGGER.FruitsClassificationType, New TextFormatDefinition(New SolidBrush(Color.LightCoral)))

How should i approach if i would like to achieve the given example? I didnt understand the thing you wrote about SplitIntoWords   , if you could give a little code snippet that would be fantastic.

BR

Peter

Dear Dess,

Its almost perfect! If this last issue stays i can live with it, but maybe you can suggest a solution to this too.

^FD is a command, but as you also wrote ^ has to be picked up separately i recorded them separately. But now the FD is not found by the coloring function, because its along with other characters. How can i make blue these too?  (see below image)
Thanks 
P

The possible suggestion that I can give in this case is to check the split words and see whether each word starts with or ends with "FD". If yes, split this word into two subwords. Thus, you will separate "FD" as a single word and it is expected to be colored as a keyword. Please give this approach a try and see how it would work for your custom scenario.